Question

解答题 a的平方乘b-ab的平方分之a的平方-b的平方除以(1+2ab分之a的平方+b的平方）

Answer 1

[(a²-b²)/(a²b-ab²)]÷[1+(a²+b²)/2ab]
=[(a+b)(a-b)/ab(a-b)]÷[(2ab+a²+b²)/2ab]
=[(a-b)/ab]÷[(a+b)²/2ab]
=[(a-b)/ab]*[2ab/(a+b)²]
=2(a-b)/(a+b)²
希望采纳！

Answer 2

(a²－b²)/(a²b－ab²)÷[1＋(a²＋b²)/2ab]
＝[(a＋b)(a－b)]/ab(a－b)÷[2ab/2ab＋(a²＋b²)/2ab]
＝(a＋b)/ab÷(a²＋b²＋2ab)/2ab
＝(a＋b)/ab÷(a＋b)²/2ab
＝(a＋b)/ab×2ab/(a＋b)²
＝2/(a＋b)

Answer 3

原式=(a^2-b^2)/(a^2b-ab^2)/[1+(a^2+b^2)/2ab]
=(a+b)(a-b)/ab(a-b)/[(a^2+b^2+2ab)/2ab]
=(a+b)/ab*2ab/(a+b)^2
=2/(a+b)

Answer 4

麻烦写清楚啊

Answer 5

您表达不清楚啊！无法理解题目！截张图来！