Question

若x＾2+x+m=(x-n)＾2,则m=?,n=?

Answer 1

x＾2+x+m=(x-n)＾2=x^2-2nx+n^2

因此
-2n=1
n^2=m
n=-1/2
m=1/4

Answer 2

x^2+x+m=x^2+x+1/4-1/4+m =(x+1/2)+m-1/4所以m-1/4=0,m=1/4-n=1/2,n=-1/2

Answer 3

∵x^2+x+m＝(x-n)^2＝x^2-2nx+n^2
∴-2n＝1，m＝n^2
∴m＝1/4，n＝-1/2