Question

用C#编写一个输入某一年的年份和月份，计算该月的天数的编程.

提示:(1)一年中的大月(1月、3月、5月、7月、8月、10月、12月)，每月的天数为31天；(2)一年中的小月(4月、6月、9月、11月)，每月的天数为30天；(3)对于2月，则要判断该年是平年还是闰年，平年的2月为28天，闰年的2月为29天。某年符合下面两个条件之一就是闰年：①年份能被400整除；②年份能被4整除，但不能被100整除。<我学这个没多久,希望不要太难理解,谢谢勒>

Answer 1

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Maker
{
class Program
{
static void Main(string[] args)
{
int a = 31;
int b = 30;
int c, mouth=0, day=0,year;
int sum=0;
do
{
Console.WriteLine("请输入年：");
year=int.Parse(Console.ReadLine());
Console.WriteLine("请输入月份：");
mouth = int.Parse(Console.ReadLine());
Console.WriteLine("请输入日数：");
day = int.Parse(Console.ReadLine());
if ((mouth < 1 || mouth > 12) || (day < 1 || day > 31)||year<=0)
{
Console.WriteLine("输入有误！");
}else
{
if(year%4!=0)
{
c = 28;
if (mouth <= 2)
{
sum = (mouth - 1) * 31 + day;
Console.WriteLine(year + "年" + mouth + "月" + day + "日是当年的" + sum + "天");
}
else
{
switch(mouth)
{
case 3:
sum =59+day;
break;
case 4:
sum = 90 + day;
break;
case 5:
sum = 120 + day;
break;
case 6:
sum = 151 + day;
break;
case 7:
sum = 181 + day;
break;
case 8:
sum = 212 + day;
break;
case 9:
sum = 243 + day;
break;
case 10:
sum = 273 + day;
break;
case 11:
sum = 303 + day;
break;
case 12:
sum = 333 + day;
break;
}
Console.WriteLine(year + "年" + mouth + "月" + day + "日是当年的" + sum + "天");
}
}else
{
if (mouth <= 2)
{
sum = (mouth - 1) * 31 + day;
}
else
{
switch (mouth)
{
case 3:
sum =59+day+1;
break;
case 4:
sum = 90 + day + 1;
break;
case 5:
sum = 120 + day + 1;
break;
case 6:
sum = 151 + day + 1;
break;
case 7:
sum = 181 + day + 1;
break;
case 8:
sum = 212 + day + 1;
break;
case 9:
sum = 243 + day + 1;
break;
case 10:
sum = 273 + day + 1;
break;
case 11:
sum = 303 + day + 1;
break;
case 12:
sum = 333 + day + 1;
break;
}
Console.WriteLine(year + "年" + mouth + "月" + day + "日是当年的" + sum + "天");
}
}
}
} while ((mouth < 1 || mouth > 12) || (day < 1 || day > 31));
}
}
}
是这样么 ？刚好我的作业上有这一题

Answer 2

按位与&例子:inta=1,b=0;a=a&b;结果a=0=====================================表达式之间的逻辑与&&例子:if(a>b&&a>c)如果a>b并且a>c则

Answer 3

你好！是要求什么界面？年月要怎么输入？C#什么版本

Answer 4

1. static void Main(string [] args){ Console.WriteLine("请输入年份："); int year = Convert.ToInt32(Console.ReadLine()); Console.WriteLine("请输入月份："); int month = Convert.ToInt32(Console.ReadLine()); switch(month) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: Console.WriteLine("{0}年{1}月有31天", year, month); break; case 4: case 6: case 9: case 11: Console.WriteLine("{0}年{1}月有30天", year, month); break; case 2: Console.WriteLine("{0}年{1}月有{2}天", year, month, (28 + (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)).GetHashCode())); break; default: Console.WriteLine("输入的月份不合法"); break; }}

Answer 5

提示里都写的很清楚了，①、将月份分为三类：31天的一类；30天的一类；然后就是2月份的。②、如果，输入的月份是2月份，就先判断下当年是否为闰年。
最后，从用户输入的年份、月份来按照①、②来计算，得到值·