已知x/y=2/7,求分式(x2-3xy+2y2)/(x2-2xy+y2)的值
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x/y=2/7
x=2y/7
(x2-3xy+2y2)/(x2-2xy+y2)
=（x-2y)(x-y)/(x-y)²
=（x-2y)/(x-y)
=(2y/7-2y)/(2y/7-y)
=12/5
x=2y/7
(x2-3xy+2y2)/(x2-2xy+y2)
=（x-2y)(x-y)/(x-y)²
=（x-2y)/(x-y)
=(2y/7-2y)/(2y/7-y)
=12/5
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