2个回答
展开全部
您好:
x^2y+xy^2
=xy(x+y)
=2/3x3
=4/3
(x^2-1)(y^2-1)
=x²y²-x²-y²+1
=(xy)²-(x²+y²)+1
=(2/3)²+1-[(x+y)²-2xy]
=13/9 -2²+2x2/3
=13/9+12/9-4
=-11/9
2a-1/2ab^2
=1/2a(4-b²)
=1/2a(2+b)(2-b)
如果本题有什么不明白可以追问,如果满意记得采纳
如果有其他问题请另发或点击向我求助,答题不易,请谅解,谢谢。
祝学习进步!
x^2y+xy^2
=xy(x+y)
=2/3x3
=4/3
(x^2-1)(y^2-1)
=x²y²-x²-y²+1
=(xy)²-(x²+y²)+1
=(2/3)²+1-[(x+y)²-2xy]
=13/9 -2²+2x2/3
=13/9+12/9-4
=-11/9
2a-1/2ab^2
=1/2a(4-b²)
=1/2a(2+b)(2-b)
如果本题有什么不明白可以追问,如果满意记得采纳
如果有其他问题请另发或点击向我求助,答题不易,请谅解,谢谢。
祝学习进步!
更多追问追答
追问
分解因式(x-y)^2-2(y-x)+1
追答
(x-y)^2-2(y-x)+1
=(x-y)^2+2(x-y)+1
=(x-y+1)^2
展开全部
x+y=2
xy=2/3
(1) x²y+xy²
=xy(x+y)
=2/3*2
=4/3
(2)(x²-1)(y²-1)
=x²y²-x²-y²+1
=(xy)²-(x²+y²)+1
=(xy)²-(x+y)²+2xy+1
=4/9-4+4/3+1
=3-4
= -1
(3)2a-1/2ab²=a(2-b²/2)
=(4-b²)*a/2
=(2+b)(2-b)*a/2
xy=2/3
(1) x²y+xy²
=xy(x+y)
=2/3*2
=4/3
(2)(x²-1)(y²-1)
=x²y²-x²-y²+1
=(xy)²-(x²+y²)+1
=(xy)²-(x+y)²+2xy+1
=4/9-4+4/3+1
=3-4
= -1
(3)2a-1/2ab²=a(2-b²/2)
=(4-b²)*a/2
=(2+b)(2-b)*a/2
更多追问追答
追问
分解因式(x-y)^2-2(y-x)+1
追答
(x-y)²-2(y-x)+1
=(x-y)²+2(x-y)+1
=(x-y+1)²
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