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初一数学!!!!!求解!急急急急急急急急急!谢谢!~
2003^2-2004×2002a^2·a^n+1-a·a^2·a^n(x+y)(x^2-xy+y^2)(3x-y)(y+3x)(4x-3y)(4x+3y)(x+y-z)...
2003^2-2004×2002
a^2·a^n+1-a·a^2·a^n
(x+y)(x^2-xy+y^2)
(3x-y)(y+3x)(4x-3y)(4x+3y)
(x+y-z)^2 展开
a^2·a^n+1-a·a^2·a^n
(x+y)(x^2-xy+y^2)
(3x-y)(y+3x)(4x-3y)(4x+3y)
(x+y-z)^2 展开
6个回答
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1.原式=2003^2 - (2003+1)(2003-1)=2003^2 - (2003^2 - 1)=2003^2 - 2003^2 + 1=1
2.原式=a^(2+n+1) - a^(1+2+n)=0
3.原式=x^3 + y^3
4.原式=[(3x)^2 - y^2][(4x)^2 - (3y)^2]=(9x^2 - y^2)(16x^2 - 9y^2)=144x^4 - 97x^2y^2 + 9y^4
5.原式=x^2 + y^2 + z^2 + 2xy - 2xz - 2yz
2.原式=a^(2+n+1) - a^(1+2+n)=0
3.原式=x^3 + y^3
4.原式=[(3x)^2 - y^2][(4x)^2 - (3y)^2]=(9x^2 - y^2)(16x^2 - 9y^2)=144x^4 - 97x^2y^2 + 9y^4
5.原式=x^2 + y^2 + z^2 + 2xy - 2xz - 2yz
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2003^2-2004×2002
解,得:
==2003^2-(2003+1)2002
==2003^2-2003*2002-2002
==2003(2003-2002)-2002
==2003-2002
==1
a^2·a^n+1-a·a^2·a^n
解,得:
==a^2·a^n*a^2·a^n-a·a^2·a^n
==a^2·a^n(a^2·a^n-1)
(x+y)(x^2-xy+y^2)
解,得:
(X+Y)(X^2-XY+Y^2)
=(x*x^2-x*xy+x*y^2)+(x^2y-xy^2+y^3)
=x^3+y^3
(3x-y)(y+3x)(4x-3y)(4x+3y)
解,得:
(3X-Y)(Y+3X)-(4X-3Y)(4X+3Y)
=[(3X)^2-Y^2]-[(4X)^2-(3Y)^2]
=(9X^2-Y^2)-(16X^2-9Y^2)
=8Y²-7X²
(x+y-z)^2
解,得:
解:
(x+y-z)^2
=(x+y)²-2(x+y)z+z²
=x²+y²+2xy-2xz-2yz+z²
解,得:
==2003^2-(2003+1)2002
==2003^2-2003*2002-2002
==2003(2003-2002)-2002
==2003-2002
==1
a^2·a^n+1-a·a^2·a^n
解,得:
==a^2·a^n*a^2·a^n-a·a^2·a^n
==a^2·a^n(a^2·a^n-1)
(x+y)(x^2-xy+y^2)
解,得:
(X+Y)(X^2-XY+Y^2)
=(x*x^2-x*xy+x*y^2)+(x^2y-xy^2+y^3)
=x^3+y^3
(3x-y)(y+3x)(4x-3y)(4x+3y)
解,得:
(3X-Y)(Y+3X)-(4X-3Y)(4X+3Y)
=[(3X)^2-Y^2]-[(4X)^2-(3Y)^2]
=(9X^2-Y^2)-(16X^2-9Y^2)
=8Y²-7X²
(x+y-z)^2
解,得:
解:
(x+y-z)^2
=(x+y)²-2(x+y)z+z²
=x²+y²+2xy-2xz-2yz+z²
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2003^2-2004×2002
=2003方-(2003+1)(2003-1)
=1
a^2·a^n+1-a·a^2·a^n
=0
(x+y)(x^2-xy+y^2)
=X立+Y立
(3x-y)(y+3x)(4x-3y)(4x+3y)
=(9X方-Y方)(16X方-9Y方)
=144X四-97X方Y方+9Y四
(x+y-z)^2
=X方+Y方+Z方+2XY-2XZ-2YZ
=2003方-(2003+1)(2003-1)
=1
a^2·a^n+1-a·a^2·a^n
=0
(x+y)(x^2-xy+y^2)
=X立+Y立
(3x-y)(y+3x)(4x-3y)(4x+3y)
=(9X方-Y方)(16X方-9Y方)
=144X四-97X方Y方+9Y四
(x+y-z)^2
=X方+Y方+Z方+2XY-2XZ-2YZ
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2003∧2-(2003+1)×(2003-1)
2003∧2-(2003+1)×(2003-1)=1
- - 唔唔,剩下的都是化简了
2003∧2-(2003+1)×(2003-1)=1
- - 唔唔,剩下的都是化简了
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