sat og test1 section7 数学部份 q8+q10
satogtest1section7数学部份8:Inanelection2.8millionvoteswerecastandeachvotewasforeitherCan...
sat og test1 section7 数学部份
8:In an election 2.8 million votes were cast and each vote was for either Candidate I or CandidateII. Candidate I received 28,000 more votes than CandidateII. What percent of the 2.8 million votes were cast for Candidate I?
A.50.05% B.50.1% C. 50.5% D. 51% E.55%
10:When 1.783 is rounded to the nearest whole number, the result is how much greater than when 1.783 is rounded to the nearest tenth?
求具体解析、步骤、最好能提供sat og 所有具体解析材料、我在网上找的都没有数学部分的解析。 急求、请尽快答复
急啊、、、求速答!!!!!!!! 展开
8:In an election 2.8 million votes were cast and each vote was for either Candidate I or CandidateII. Candidate I received 28,000 more votes than CandidateII. What percent of the 2.8 million votes were cast for Candidate I?
A.50.05% B.50.1% C. 50.5% D. 51% E.55%
10:When 1.783 is rounded to the nearest whole number, the result is how much greater than when 1.783 is rounded to the nearest tenth?
求具体解析、步骤、最好能提供sat og 所有具体解析材料、我在网上找的都没有数学部分的解析。 急求、请尽快答复
急啊、、、求速答!!!!!!!! 展开
1个回答
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8. 设投给Candidate I的票数为x,则投给Candidate II的票数为2.8*10^6-x,由题目知
x - (2.8*10^6-x) = 28000, 解得 x = 1.4 * 10^6 + 14000
从而百分比为 (1.4 * 10^6 + 14000) / 2.8*10^6 = 50.05%, 选A
10. 1.783四舍五入到最近的整数是2,1.783四舍五入到最近的0.1精度是1.8
故 (2-1.8)/1.8=1/9,即2比1.8大0.2(绝对值)或大1/9(相对值)
x - (2.8*10^6-x) = 28000, 解得 x = 1.4 * 10^6 + 14000
从而百分比为 (1.4 * 10^6 + 14000) / 2.8*10^6 = 50.05%, 选A
10. 1.783四舍五入到最近的整数是2,1.783四舍五入到最近的0.1精度是1.8
故 (2-1.8)/1.8=1/9,即2比1.8大0.2(绝对值)或大1/9(相对值)
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