数学分组分解法题目?
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1.填空:
(1)x³-x²+3x-3=(x-1)(x^2+3)
(2)15x²y-30xy²+3x-6y=3(x-2y)(5xy+1)
(3)ax²+ay²-2axy-a³=a(x-2y+a)(x-2y-a)
2.因式分解:(写出过程)
(1)x²-xy+xz-yz(有两种方法)
=(x²-xy)+(xz-yz)=x(x-y)+z(x-y)=(x-y)(x+z)
或=(x²+xz)+(-xy-yz)=x(x+z)-y(x+z)=(x+z)(x-y)
(2)4x²+1/4-9y²-2x
=(4x²-2x+1/4)-9y²=(2x-1/2)^2-(3y)^2=(2x-1/2+3y)(2x-1/2-3y)
(3)(ab+1)²-(a+b)²
=(ab+1+a+b)(ab+1-a-b)=(a+1)(b+1)(a-1)(b-1)
(1)x³-x²+3x-3=(x-1)(x^2+3)
(2)15x²y-30xy²+3x-6y=3(x-2y)(5xy+1)
(3)ax²+ay²-2axy-a³=a(x-2y+a)(x-2y-a)
2.因式分解:(写出过程)
(1)x²-xy+xz-yz(有两种方法)
=(x²-xy)+(xz-yz)=x(x-y)+z(x-y)=(x-y)(x+z)
或=(x²+xz)+(-xy-yz)=x(x+z)-y(x+z)=(x+z)(x-y)
(2)4x²+1/4-9y²-2x
=(4x²-2x+1/4)-9y²=(2x-1/2)^2-(3y)^2=(2x-1/2+3y)(2x-1/2-3y)
(3)(ab+1)²-(a+b)²
=(ab+1+a+b)(ab+1-a-b)=(a+1)(b+1)(a-1)(b-1)
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