3个回答
展开全部
u=yf(x/y)+xf(y/x)
u‘x=f'(x/y)+f(y/x)+xf'(y/x)(-y/x^2)=f'(x/y)+f(y/x)-yf'(y/x)/x
u‘'xx=f''(x/y)/y-yf'(y/x)/x^2-y[xf''(y/x)(-y/x^2)-f'(y/x)]/x^2
=f''(x/y)/y+f''(y/x)(y^2/x^3)
u''yy=f''(y/x)/x+f''(x/y)(x^2/y^3)
代入即可
u‘x=f'(x/y)+f(y/x)+xf'(y/x)(-y/x^2)=f'(x/y)+f(y/x)-yf'(y/x)/x
u‘'xx=f''(x/y)/y-yf'(y/x)/x^2-y[xf''(y/x)(-y/x^2)-f'(y/x)]/x^2
=f''(x/y)/y+f''(y/x)(y^2/x^3)
u''yy=f''(y/x)/x+f''(x/y)(x^2/y^3)
代入即可
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算出来无选项啊
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