Question

求帮助做两道数学题目~~

定积分
∫(-y²+7y)dy y大于等于0小于等于7

定积分
∫（3y-y²)dy y大于等于0小于等于3
定积分上的上下角标不好打就是第一个上7下0
第二个上3下0

Answer 1

∫[7,0] (-y²+7y)dy
=-y³/3+7y²/2 [7,0]
=-343/3+343/2
=343/6

∫[3,0] （3y-y²)dy
=3y²/2-y³/3 [3,0]
=27/2-27/3
=9/2

谢谢，希望楼主采纳！

Answer 2

∫[7,0] (-y²+7y)dy
=-y³/3+7y²/2 [7,0]
=-343/3+343/2
=343/6

∫[3,0] （3y-y²)dy
=3y²/2-y³/3 [3,0]
=27/2-27/3
=9/2

Answer 3

∫(-y²+7y)dy

=-y³/3+7y²/2 (0,7)
=(-343/3+343/2)-(0+0)
=343/6

∫（3y-y²)dy

=3y²/2-y³/3 (0,3)
=(27/2-27/3)-(0-0)
=9/2

Answer 4

343/6
9/2

Answer 5

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