Question

数学问题：若a大于2，则不等式ax大于2x-1的解集是？（求x的解集）

Answer 1

ax>2x-1(a-2)x>-1∵a>2∴a-2>0x>1/(2-a)∵f(x)=1/(2-a) (a>2) 为单调递增函数∴当a趋近于+∞是f(x)有最大值无限趋近于0且小于零∴x>0

Answer 2

∵ax>2x-1∴ax-2x>-1x(a-2)>-1又∵a>2∴a-2>0∴x>-1/(a-2)

Answer 3

ax>2x-1(a-2)x>-1∵a>2∴a-2>0x>-1/(a-2)

Answer 4

x>-1/(a-2)