Question

cosx的原函数怎么求？

Answer 1

解：∫cosxdx
=∫[-(-cosx)]dx
=-∫(-cosx)dx
=-sinx+C (C为常数)

Answer 2

引用qian_yi1e的回答：
解：∫cosxdx
=∫[-(-cosx)]dx
=-∫(-cosx)dx
=-sinx+C (C为常数)

cosx的原函数是sinx