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a1+a13=2a7
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b1+b13=2b7
分子分母同时乘以13
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an =a1+(n-1)d1
bn =b1+(n-1)d2
Sn=a1+a2+...+an = [2a1+(n-1)d1] n/2
Tn=b1+b2+...+bn = [2b1+(n-1)d2] n/2
Sn/Tn = (3n+5)/(2n+3)
[2a1+(n-1)d1]/[2b1+(n-1)d2] = (3n+5)/(2n+3)
n=13
[2a1+12d1]/[2b1+12d2] = 44/空没29
(a1+6d1)/大戚(b1+6d2) = 44/斗仿纳29
a7/b7 =44/29
bn =b1+(n-1)d2
Sn=a1+a2+...+an = [2a1+(n-1)d1] n/2
Tn=b1+b2+...+bn = [2b1+(n-1)d2] n/2
Sn/Tn = (3n+5)/(2n+3)
[2a1+(n-1)d1]/[2b1+(n-1)d2] = (3n+5)/(2n+3)
n=13
[2a1+12d1]/[2b1+12d2] = 44/空没29
(a1+6d1)/大戚(b1+6d2) = 44/斗仿纳29
a7/b7 =44/29
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