求大神做数学
1个回答
追答
答:
(1)m=(sinx,cosx),n=(1,-1)
m.n=sinx-cosx=1/5
所以:sinx-cosx=1/5
两边平方:1-2sinxcosx=1/25
所以:2sinxcosx=24/25
所以:(sinx+cosx)²=1+2sinxcosx=49/25
所以:sinx+cosx=7/5
sin(x+π/2)+cos(x+3π/3)
=sin[π-(π/2-x)]+cos[2π-(π/2-x)]
=cosx+sinx
=7/5
(2)
(sin2x+2sin²x)/(1-tanx)
=(2sinxcosx+2sinxsinx)cosx/(cosx-sinx)
=2sinxcosx(cosx+sinx)/(cosx-sinx)
=(24/25)*(7/5)/(-1/5)
=-168/25
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