Question

(C程序)输入a,b,c求一元二次方程ax2+bx+c=0的两个实根(不考虑无解的情况).

//splitnum
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
main()
{
double a,x,x1,x2,b,c;
x1=-b+sqrt(b*b-4*a*c)/(2*a);
x2=-b-sqrt(b*b-4*a*c)/(2*a);
printf("%d\n",x);
printf("%d\n",a);
printf("%d\n",b);
printf("%d\n",c);
system("pause");
}
哪里错了?

Answer 1

#include<stdio.h>
#include<stdlib.h>
#include<math.h>
main()
{
double a,x1,x2,b,c;
scanf("%lf%lf%lf",&a,&b,&c);
x1=-b+sqrt(b*b-4*a*c)/(2*a);
x2=-b-sqrt(b*b-4*a*c)/(2*a);
//printf("%d\n",x);
printf("a=%lf\n",a);
printf("b=%lf\n",b);
printf("c=%lf\n",c);
printf("x1=%f\n",x1);
printf("x2=%f\n",x2);
system("pause");
}

少输入。%d

Answer 2

少输入初始化
double的输入输出用%lf