先化简在求值,(x/x-1-1/x²-x)÷(x+1)。其中x=√2.
3个回答
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[x/(x-1)-1/(x²-x)]÷(x+1)
=[x²/x(x-1)-1/x(x-1)]÷(x+1)
=[(x²-1)/x(x-1)]÷(x+1)
=[(x+1)(x-1)/x(x-1)]÷(x+1)
=[(x+1)/x]×1/(x+1)
=1/x
=1/√2=√2/2.
=[x²/x(x-1)-1/x(x-1)]÷(x+1)
=[(x²-1)/x(x-1)]÷(x+1)
=[(x+1)(x-1)/x(x-1)]÷(x+1)
=[(x+1)/x]×1/(x+1)
=1/x
=1/√2=√2/2.
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原式=(x²-1)/x(x-1)*1/(x+1)
=(x+1)(x-1)/x(x-1)*1/(x+1)
=(x+1)/x*1/(x+1)
=1/x
=1/√2
=√2/2
=(x+1)(x-1)/x(x-1)*1/(x+1)
=(x+1)/x*1/(x+1)
=1/x
=1/√2
=√2/2
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