Question

计算3(4+1)(4²+1)(4的四次方+1)……(4的4096次方+1)的值

亲，要快一点哦！

Answer 1

3(4+1)(4^2+1)(4^4+1)…(4^4096+1)
=（顷运空4-1）(4+1)(4^2+1)(4^4+1)…(4^4096+1)
=（4^2-1）(4^2+1)(4^4+1)…(4^4096+1)
=(4^4-1)(4^4+1)(4^6+1)…雀瞎悄坦(4^4096+1)
=……=(4^4096-1)(4^4096+1)
=(4^8192-1)
谢谢

Answer 2

3(4+1)(4²纤液+1)(4的毁绝物四次方+1)……(4的4096次方+1)
=(4-1)(4+1)(4²+1)(4的四次方+1)……(4的宏戚4096次方+1)
=(4的4096次方+1)(4的4096次方-1)
=4的8192次方-1

Answer 3

（4的8192次方）-1