Question

先化简代数式（a-1分之a+1+a^2-2a+分之1）÷a-1分之a，然后选取一个适当的a值代入求值

Answer 1

原式=[(a+1)/(a-1)+1/(a-1)^2]÷a/(a-1)
=a^2/(a-1)^2*(a-1)/a
=a/(a-1)
令a=2，
原式=2/(2-1)=2。

Answer 2

[(a+1)/(a-1)+1/(a-1)�0�5]×(a-1)/a
=(a�0�5-1+1)/(a-1)�0�5×(a-1) /a
=a/(a-1)
当a=2时
原式=2/(2-1)=2