Question

求函数y=sin(2x+π/6)-cos(2x+π/3)的最小周期和最大值，详解，谢谢`~

很急的，在线的帮帮忙~谢谢

Answer 1

y=sin(2x+π/6)-cos(2x+π/3)
=sin2xcosπ/6+cos2xsinπ/6-(cos2xcosπ/3-sin2xsinπ/3)
=√3sin2x
最小正周期π和最大值√3