Question

因式分解求答案，我跪了，快点啊

a²-4a+4-c²
3x²y+28y²+7xy²+12xy
a四次方-3a²-4
6x²-17x-10
5x²-13xy-6y²
6﹙m-n﹚ ²-10m+10n-4
x³-2x ²+xy²-x
x²+xy-2y²
3y^n-1-6y^n-2-9y^n-3

Answer 1

a²-4a+4-c²=(a-2)^2-c^2=(a-2+c)(a-2-c)
3x²y+28y²+7xy²+12xy==7y^2(4+x)+3xy(x+4)=(7y+3x)(x+4)y
a四次方-3a²-4=(a^2-4)(a^2+1)=(a+2)(a-2)(a^2+1)
6x²-17x-10=(3x+1)(2x-10)=2(3x+1)(x-5)
5x²-13xy-6y²=(5x+2y)(x-3y)
6﹙m-n﹚ ²-10m+10n-4=[2(m-n)-4][3(m-n)+1]
x³-2x ²+xy²-x=x(x^2-2x+y^2-1)
x²+xy-2y²=(x+2y)(x-y)
3y^n-1-6y^n-2-9y^n-3=3y^(n-3) (y-3)(y+1)
希望采纳！

Answer 2

a²-4a+4-c²
=(a-2)^2-c^2
=(a-2+c)(a-2-c)
3x²y+28y²+7xy²+12xy
=y(3x^2+12x+28y+7xy)
=y(3x(x+4)+7y(x+4))
=y(x+4)(3x+7y)
a四次方-3a²-4
=(a^2-4)(a^2+1)
=(a+2)(a-2)(a^2+1)
6x²-17x-10
=(2x+1)(3x-10)
5x²-13xy-6y²
=(x-3y)(5x+2y)
6﹙m-n﹚ ²-10m+10n-4
=6(m-n)*(m-n)-10(m-n)-4
=[(m-n)-2]*[6(m-n)+2]
=(m-n-2)(6m-6n+2)
x³-2x ²+xy²-x
=x(x^2-2x+y^2-1)
=x(x^2-2x+1+y^2-2)
(这道题有没有打错？）
x²+xy-2y²
=(x+2y)(x-y)
3y^n-1-6y^n-2-9y^n-3
3y^(n-1)-6y^(n-2)-9y^(n-3)
=3y^2*y^(n-1)-6y*y^(n-3)-9y^(n-3)
=3y^(n-3)(y^2-6y+9)
=3y^(n-3)(y-3)^2

Answer 3

1. a²-4a+4-c²
   解：原式=（a-2）²;-c²            

                 =（a -2+c）（a -2-c）

2. 3x²y+28y²+7xy²+12xy
   解：原式=7y²（4+x）+3xy（4+x）

                 =（7y²+3xy）（4+x）

                 =y（7y+3x)(4+x)

Answer 4

a²-4a+4-c²
=(a-2)²-c²
=(a-2+c)(a-2-c)
3x²y+28y²+7xy²+12xy
=(3x²y+12xy)+(28y²+7xy²)
=3xy(x+4)+7y²(x+4)
=(x+4)(3xy+7y²)
=y(x+4)(3x+7)
a四次方-3a²-4
=(a^2-4)(a²+1)
=(a+2)(a-2)(a²+1)
6x²-17x-10
=(2x+1)(3x-10)
5x²-13xy-6y²
=(5x+2y)(x-3y)
6﹙m-n﹚ ²-10m+10n-4
=6﹙m-n﹚ ²-10(m-n)-4
=[6(m-n)+2][(m-n)-2]
=(6m-6n+2)(m-n-2)
x³-2x ²+xy²-x
=
x²+xy-2y²
=(x-y)(x+2y)
3y^n-1-6y^n-2-9y^n-3
=3y^n-1(1-2y^-1-3y^-2)

Answer 5

你忘了先提公因式吧，这样也许会做出来