
a2/3+b 2/3=4 x=a+3a1/3b2/3 y=b+3a2/3b1/3 求(x+y)2/3+(x-y)2/3 注:所有的分数都为指数
2013-10-22
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x+y=a+3a^(1/3)b^(2/3) +b+3a^(2/3)b(1/3)
=(a^1/3)�0�6+3a^(2/3)b(1/3)+3a^(1/3)b^(2/3)+(b^1/3)�0�6
=(a^1/3+b^1/3)�0�6
∴(x+y)^(2/3)=〔(a^1/3+b^1/3)�0�6〕^2/3=(a^1/3+b^1/3)�0�5
=a^(2/3)+2a^(1/3)b^(1/3)+b^(2/3)
=4+2a^(1/3)b^(1/3)
x-y=a+3a^(1/3)b^(2/3) -b-3a^(2/3)b(1/3)
=(a^1/3)�0�6-3a^(2/3)b(1/3)+3a^(1/3)b^(2/3)-(b^1/3)�0�6
=(a^1/3-b^1/3)�0�6
∴(x-y)^(2/3)=〔(a^1/3-b^1/3)�0�6〕^2/3=(a^1/3-b^1/3)�0�5
=a^(2/3)-2a^(1/3)b^(1/3)+b^(2/3)
=4-2a^(1/3)b^(1/3)
∴(x+y)^(2/3)+(x-y)^(2/3)=4+2a^(1/3)b^(1/3)+4-2a^(1/3)b^(1/3)=8
=(a^1/3)�0�6+3a^(2/3)b(1/3)+3a^(1/3)b^(2/3)+(b^1/3)�0�6
=(a^1/3+b^1/3)�0�6
∴(x+y)^(2/3)=〔(a^1/3+b^1/3)�0�6〕^2/3=(a^1/3+b^1/3)�0�5
=a^(2/3)+2a^(1/3)b^(1/3)+b^(2/3)
=4+2a^(1/3)b^(1/3)
x-y=a+3a^(1/3)b^(2/3) -b-3a^(2/3)b(1/3)
=(a^1/3)�0�6-3a^(2/3)b(1/3)+3a^(1/3)b^(2/3)-(b^1/3)�0�6
=(a^1/3-b^1/3)�0�6
∴(x-y)^(2/3)=〔(a^1/3-b^1/3)�0�6〕^2/3=(a^1/3-b^1/3)�0�5
=a^(2/3)-2a^(1/3)b^(1/3)+b^(2/3)
=4-2a^(1/3)b^(1/3)
∴(x+y)^(2/3)+(x-y)^(2/3)=4+2a^(1/3)b^(1/3)+4-2a^(1/3)b^(1/3)=8
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