Question

因式分解 急急急急急急急急急!

(1) a4+16b4
(2) (c-a)2-4(b-c)(a-b)
(3) x3-9x+8
(4) x3+2x2-5x-6

字母和括号后的数字均为几次方
大家帮帮忙啊，真的很急，如果有过程最好，没有的话一定要给我正确的答案

Answer 1

(1)=a^4+16a^2b^2+16b^4-16a^2b^2
=(a^2+4b^2)^2-16a^2b^2

(2)=c^2-2ac+a^2-4ab+4b^2+4ac-4bc
=(a^2-4ab+4b^2)+c^2+2ac-4bc
=(a-2b)^2+c^2+2c(a-2b)
=[c+(a-2b)]^2=(c+a-2b)^2

(3)

(4)=x(x^2+2x+1-1-5)-6
=x[(x+1)^2-6]-6
=x(x+1)^2-6x-6
=x(x+1)^2-6(x+1)
=应该还可以再划，我好久没做了，都忘记了

Answer 2

(1)a4+16b4
=a^4+8a^2b^2+16b^4-8a^2b^2
=(a^2+4b^2)^2-8a^2b^2
= (a2+4b2+2√2ab)(a2+4b2-2√2ab)

(2)=c^2-2ac+a^2-4ab+4b^2+4ac-4bc
=(a^2-4ab+4b^2)+c^2+2ac-4bc
=(a-2b)^2+c^2+2c(a-2b)
=[c+(a-2b)]^2
=(c+a-2b)^2

(3)x3-9x+8
=(x3-x2)+(x2-x)-(8x-8)
=(x-1)(x2+x-8)

(4)x3+2x2-5x-6
=(x3+x2)+(x2-5x-6)
=x2(x+1)+(x-6)(x+1)
=(x+1)(x2+x-6)
=(x+1)(x-2)(x+3)