Question

数学化简：【x-2分之5减（x-2）】除（x²-2x分之x²-6x+9）加x-3分之3x

Answer 1

错了吧，是-x-2，没有括号吧

[5/(x-2)-x-2]÷(x²-6x+9)/(x²-2x)+3x(x-3)
=[5/(x-2)-(x+2)]÷(x²-6x+9)/(x²-2x)+3x(x-3)
=[5-(x+2)(x-2)]/(x-2)÷(x-3)²/x(x-2)+3x(x-3)
=(5-x²+4)/(x-2)*x(x-2)/(x-3)²+3x(x-3)
=-(x²-9)/(x-2)*x(x-2)/(x-3)²+3x(x-3)
=-(x+3)(x-3)/(x-2)*x(x-2)/(x-3)²+3x(x-3)

=-x(x+3)/(x-3)+3x(x-3)
=(-x²-3x+3x)/(x-3)
=-x²/(x-3)

追问

括号是为了分辨开。减（x-2）也就是-x-2

追答

哦，下次不要这样写
因为这个不一样的
-(x-2)=-x+2，不是-x-2