Question

用matlab怎么在圆域x^2+y^2<=1上，画出函数z=x*y的图像,

Answer 1

[theta r]=meshgrid(linspace(0,2*pi,100),linspace(0,1,20));

[x y]=pol2cart(theta,r);

z=x.*y;

mesh(x,y,z);

Answer 2

[r,t]=meshgrid(0:0.1:1,0:0.02:2*pi);

x=r.*cos(t);

y=r.*sin(t);

z=x.*y;

mesh(x,y,z)