tanπ/9+tan2π/9+根号3tanπ/9tan2π/9=?
1个回答
展开全部
tanπ/9+tan2π/9+√3tanπ/9tan2π/9
=tan(π/9+2π/9)(1-tanπ/9tan2π/9) +√3tanπ/9tan2π/9
=tanπ/3(1-tanπ/9tan2π/9) +√3tanπ/9tan2π/9
=√3(1-tanπ/9tan2π/9) +√3tanπ/9tan2π/9
=√3-√3tanπ/9tan2π/9 +√3tanπ/9tan2π/9
=√3
=tan(π/9+2π/9)(1-tanπ/9tan2π/9) +√3tanπ/9tan2π/9
=tanπ/3(1-tanπ/9tan2π/9) +√3tanπ/9tan2π/9
=√3(1-tanπ/9tan2π/9) +√3tanπ/9tan2π/9
=√3-√3tanπ/9tan2π/9 +√3tanπ/9tan2π/9
=√3
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询