Question

求可逆矩阵P，使P－1AP为对角矩阵

1 1 -2
-1 -3 1
-2 0 -1

Answer 1

= (3-λ)[(2-λ)(3-λ)-2] = (3-λ)(λ^2-5λ+4) = (3-λ)(λ-1)(λ-4) 所以A的特征值为1,3,4 (A-E)X=0 的基础解系为 (2,1,1)^T (A-3E)X=0 的...

追问

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