Question

计算： x分之3-1-x分之6-x²-x分之x+5.

（-c分之a²b））³×（ab分之-c²）负²÷（a分之bc）四次方.
x+1分之x-4=x-3分之x-2.
x-1分之x+1-x²-1分之4=1.

Answer 1

x分之3-1-x分之6-x²-x分之x+5.
=3/x+6/(x-1)-(x+5)/x(x-1)
=[3(x-1)+6x-(x+5)]/x(x-1)
=(3x-3+6x-x-5)/x(x-1)
=8(x-1)/x(x-1)
=8/x

=-a的6次方b³/c³ ×a²b²/c的4次方 ×a的4次方/b的4次方c的4次方
=-a的12次方/c的11次方

两边乘以(x+1)(x-3)得
(x-4)(x-3)=(x-2)(x+1)
x²-7x+12=x²-x-2
-6x=-14
x=7/3
经检验：x=7/3是方程的解

两边乘以(x+1)(x-1)得
(x+1)²-4=(x+1)(x-1)
x²+2x+1-4=x²-1
2x=2
x=1
经检验：x=1是增根
∴原方程无解