先化简，再求值：x/x²-2x+1÷{（x+1/x²-1）+1}，其中x=根号2+1
展开全部
x/(x²-2x+1)÷[(x+1)/(x²-1)+1]
=x/(x-1)²÷[(x+1)+(x²-1)]/(x²-1)
=x/(x-1)²÷(x²+x)/[(x+1)(x-1)]
=x/(x-1)²÷[x(x+1)]/[(x+1)(x-1)]
=x/(x-1)²÷x/(x-1)
=x/(x-1)²·(x-1)/x
=1/(x-1)
=1/√2
=√2/2
=x/(x-1)²÷[(x+1)+(x²-1)]/(x²-1)
=x/(x-1)²÷(x²+x)/[(x+1)(x-1)]
=x/(x-1)²÷[x(x+1)]/[(x+1)(x-1)]
=x/(x-1)²÷x/(x-1)
=x/(x-1)²·(x-1)/x
=1/(x-1)
=1/√2
=√2/2
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
原式=x/(x-1)²÷(x+1+x²-1)/(x²-1)
=x/(x-1)²*(x²-1)/(x+x²)
=x/(x-1)²*(x+1)(x-1)/x(x+1)
=x/(x-1)²*(x-1)/x
=1/(x-1)
=1/(√2+1-1)
=√2/2
=x/(x-1)²*(x²-1)/(x+x²)
=x/(x-1)²*(x+1)(x-1)/x(x+1)
=x/(x-1)²*(x-1)/x
=1/(x-1)
=1/(√2+1-1)
=√2/2
来自：求助得到的回答
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
x/x平方-2x+1÷{（x+1/x²-1）+1}，
=x/(x-1)平方 ÷{1/(x-1)+1}
=x/(x-1)平方 ÷x/(x-1)
=x/(x-1)平方 ×(x-1)/x
=1/(x-1)
x=根号2+1
所以
原式=1/(√2+1-1)=1/√2=√2/2
=x/(x-1)平方 ÷{1/(x-1)+1}
=x/(x-1)平方 ÷x/(x-1)
=x/(x-1)平方 ×(x-1)/x
=1/(x-1)
x=根号2+1
所以
原式=1/(√2+1-1)=1/√2=√2/2
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
更多回答（1）
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
