Question

已知x=根号3-1分之2,求x的平方-x+1

Answer 1

已知x=根号3-1分之2,
x=2(√3+1)/(√3+1)(√3-1)
x=(√3+1)
x的平方-x+1
=x^2-2x+1+x
=(x-1)^2+x
=(√3+1-1)^2+√3+1
=3+√3+1
=4+√3