
1个回答
展开全部
sinα+cosα=√2/3 ,
1+2sinαcosα=2/9,有sinαcosα=-7/18.
又
sin^3(π/2-α)+cos^3(π/2+α)
=cos^3 α-sin^3 α
=(cosα-sinα)(1+sinαcosα)
=√(1-2sinαcosα)(1+sinαcosα)
=4/3×11/18
=22/27.
1+2sinαcosα=2/9,有sinαcosα=-7/18.
又
sin^3(π/2-α)+cos^3(π/2+α)
=cos^3 α-sin^3 α
=(cosα-sinα)(1+sinαcosα)
=√(1-2sinαcosα)(1+sinαcosα)
=4/3×11/18
=22/27.
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询