初一数学分组分解法~急!!! 20
1。分组时能应预见下一步分解的可能性1。______2._______3.________2.分解因式(用分组分解):x^2-xy-2y^2-x-yx^3+2x^2-5x...
1。分组时能应预见下一步分解的可能性1。______2._______3.________
2.分解因式(用分组分解):
x^2-xy-2y^2-x-y
x^3+2x^2-5x-6
a^2-6ab+9b^2-4a+12b+4
x^2+2xy+y^2-x-y-1/4
a^2-10ab+25b^2-5a+25b-6
3.对多项式4x^2+2x-y^2-y用分组分解法分解因式,下面分组分解正确的是( )
A.(4x^2+2x)-(y^2=y) B.4x^2+(2x-y^2-y)
C.(4x^2-y^2)+(2x-y) D.(4x^2-y)(2x-y^2)
4.将x^3-x^2+x-1分解因式时,错误的分组方法是( )
A.(x^3-x^2)+(x-1) B.(x^3+x)+(-x^2-1)
C.(x^3-1)+(-x^2+x) d.x^3-(x^2-x+1) 展开
2.分解因式(用分组分解):
x^2-xy-2y^2-x-y
x^3+2x^2-5x-6
a^2-6ab+9b^2-4a+12b+4
x^2+2xy+y^2-x-y-1/4
a^2-10ab+25b^2-5a+25b-6
3.对多项式4x^2+2x-y^2-y用分组分解法分解因式,下面分组分解正确的是( )
A.(4x^2+2x)-(y^2=y) B.4x^2+(2x-y^2-y)
C.(4x^2-y^2)+(2x-y) D.(4x^2-y)(2x-y^2)
4.将x^3-x^2+x-1分解因式时,错误的分组方法是( )
A.(x^3-x^2)+(x-1) B.(x^3+x)+(-x^2-1)
C.(x^3-1)+(-x^2+x) d.x^3-(x^2-x+1) 展开
3个回答
展开全部
1. (分组后可直接提公因式)
(分组后可运用公式)
(分组后既可提公因式又可运用公式)
2. x^2-xy-2y^2-x-y
=(x^2-y^2)-(xy+y^2)-(x+y)
=(x+y)(x-y)-y(x+y)-(x+y)
=(x+y)(x-y-y-1)
=(x+y)(x-2y-1)
x^3+2x^2-5x-6
=(x^3+2x^2+x)-(6x+6)
=x(x+1)^2-6(x+1)
=(x+1)(x^2+x-6)
=(x+1)[(x^2+3x)-(2x+6)]
=(x+1)[x(x+3)-2(x+3)]
=(x+1)(x+3)(x-2)
a^2-6ab+9b^2-4a+12b+4
=(a^2-6ab+9b^2)-(4a-12b)+4
=(a-3b)^2-4(a-3b)+4
=(a-3b-2)^2
x^2+2xy+y^2-x-y-1/4
=(x^2+2xy+y^2)-(x+y)-1/4
=(x+y)^2-(x+y)-1/4
=(x+y-1/2)^2
a^2-10ab+25b^2-5a+25b-6
=(a^2-10ab+25b^2)-(5a-25b)-6
=(a-5b)^2-[(6a-30b)-(a-5b)]-6
=[(a-5b)^2+(a-5b)]-6[(a-5b)+1]
=(a-5b)(a-5b+1)-6(a-5b+1)
=(a-5b+1)(a-5b-6)
3.(C) 4.(D)
(分组后可运用公式)
(分组后既可提公因式又可运用公式)
2. x^2-xy-2y^2-x-y
=(x^2-y^2)-(xy+y^2)-(x+y)
=(x+y)(x-y)-y(x+y)-(x+y)
=(x+y)(x-y-y-1)
=(x+y)(x-2y-1)
x^3+2x^2-5x-6
=(x^3+2x^2+x)-(6x+6)
=x(x+1)^2-6(x+1)
=(x+1)(x^2+x-6)
=(x+1)[(x^2+3x)-(2x+6)]
=(x+1)[x(x+3)-2(x+3)]
=(x+1)(x+3)(x-2)
a^2-6ab+9b^2-4a+12b+4
=(a^2-6ab+9b^2)-(4a-12b)+4
=(a-3b)^2-4(a-3b)+4
=(a-3b-2)^2
x^2+2xy+y^2-x-y-1/4
=(x^2+2xy+y^2)-(x+y)-1/4
=(x+y)^2-(x+y)-1/4
=(x+y-1/2)^2
a^2-10ab+25b^2-5a+25b-6
=(a^2-10ab+25b^2)-(5a-25b)-6
=(a-5b)^2-[(6a-30b)-(a-5b)]-6
=[(a-5b)^2+(a-5b)]-6[(a-5b)+1]
=(a-5b)(a-5b+1)-6(a-5b+1)
=(a-5b+1)(a-5b-6)
3.(C) 4.(D)
展开全部
1. (分组后可直接提公因式)
(分组后可运用公式)
(分组后既可提公因式又可运用公式)
2. x^2-xy-2y^2-x-y
=(x^2-y^2)-(xy+y^2)-(x+y)
=(x+y)(x-y)-y(x+y)-(x+y)
=(x+y)(x-y-y-1)
=(x+y)(x-2y-1)
x^3+2x^2-5x-6
=(x^3+2x^2+x)-(6x+6)
=x(x+1)^2-6(x+1)
=(x+1)(x^2+x-6)
=(x+1)[(x^2+3x)-(2x+6)]
=(x+1)[x(x+3)-2(x+3)]
=(x+1)(x+3)(x-2)
a^2-6ab+9b^2-4a+12b+4
=(a^2-6ab+9b^2)-(4a-12b)+4
=(a-3b)^2-4(a-3b)+4
=(a-3b-2)^2
x^2+2xy+y^2-x-y-1/4
=(x^2+2xy+y^2)-(x+y)-1/4
=(x+y)^2-(x+y)-1/4
=(x+y-1/2)^2
a^2-10ab+25b^2-5a+25b-6
=(a^2-10ab+25b^2)-(5a-25b)-6
=(a-5b)^2-[(6a-30b)-(a-5b)]-6
=[(a-5b)^2+(a-5b)]-6[(a-5b)+1]
=(a-5b)(a-5b+1)-6(a-5b+1)
=(a-5b+1)(a-5b-6)
3.(C) 4.(D)
(分组后可运用公式)
(分组后既可提公因式又可运用公式)
2. x^2-xy-2y^2-x-y
=(x^2-y^2)-(xy+y^2)-(x+y)
=(x+y)(x-y)-y(x+y)-(x+y)
=(x+y)(x-y-y-1)
=(x+y)(x-2y-1)
x^3+2x^2-5x-6
=(x^3+2x^2+x)-(6x+6)
=x(x+1)^2-6(x+1)
=(x+1)(x^2+x-6)
=(x+1)[(x^2+3x)-(2x+6)]
=(x+1)[x(x+3)-2(x+3)]
=(x+1)(x+3)(x-2)
a^2-6ab+9b^2-4a+12b+4
=(a^2-6ab+9b^2)-(4a-12b)+4
=(a-3b)^2-4(a-3b)+4
=(a-3b-2)^2
x^2+2xy+y^2-x-y-1/4
=(x^2+2xy+y^2)-(x+y)-1/4
=(x+y)^2-(x+y)-1/4
=(x+y-1/2)^2
a^2-10ab+25b^2-5a+25b-6
=(a^2-10ab+25b^2)-(5a-25b)-6
=(a-5b)^2-[(6a-30b)-(a-5b)]-6
=[(a-5b)^2+(a-5b)]-6[(a-5b)+1]
=(a-5b)(a-5b+1)-6(a-5b+1)
=(a-5b+1)(a-5b-6)
3.(C) 4.(D)
参考资料: 谢谢楼上的朋友.
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展开全部
1. (分组后可直接提公因式)
(分组后可运用公式)
(分组后既可提公因式又可运用公式)
2. x^2-xy-2y^2-x-y
=(x^2-y^2)-(xy+y^2)-(x+y)
=(x+y)(x-y)-y(x+y)-(x+y)
=(x+y)(x-y-y-1)
=(x+y)(x-2y-1)
x^3+2x^2-5x-6
=(x^3+2x^2+x)-(6x+6)
=x(x+1)^2-6(x+1)
=(x+1)(x^2+x-6)
=(x+1)[(x^2+3x)-(2x+6)]
=(x+1)[x(x+3)-2(x+3)]
=(x+1)(x+3)(x-2)
a^2-6ab+9b^2-4a+12b+4
=(a^2-6ab+9b^2)-(4a-12b)+4
=(a-3b)^2-4(a-3b)+4
=(a-3b-2)^2
x^2+2xy+y^2-x-y-1/4
=(x^2+2xy+y^2)-(x+y)-1/4
=(x+y)^2-(x+y)-1/4
=(x+y-1/2)^2
a^2-10ab+25b^2-5a+25b-6
=(a^2-10ab+25b^2)-(5a-25b)-6
=(a-5b)^2-[(6a-30b)-(a-5b)]-6
=[(a-5b)^2+(a-5b)]-6[(a-5b)+1]
=(a-5b)(a-5b+1)-6(a-5b+1)
=(a-5b+1)(a-5b-6)
3.(C) 4.(D)
参考资料:谢谢楼上的楼上的朋友.
(分组后可运用公式)
(分组后既可提公因式又可运用公式)
2. x^2-xy-2y^2-x-y
=(x^2-y^2)-(xy+y^2)-(x+y)
=(x+y)(x-y)-y(x+y)-(x+y)
=(x+y)(x-y-y-1)
=(x+y)(x-2y-1)
x^3+2x^2-5x-6
=(x^3+2x^2+x)-(6x+6)
=x(x+1)^2-6(x+1)
=(x+1)(x^2+x-6)
=(x+1)[(x^2+3x)-(2x+6)]
=(x+1)[x(x+3)-2(x+3)]
=(x+1)(x+3)(x-2)
a^2-6ab+9b^2-4a+12b+4
=(a^2-6ab+9b^2)-(4a-12b)+4
=(a-3b)^2-4(a-3b)+4
=(a-3b-2)^2
x^2+2xy+y^2-x-y-1/4
=(x^2+2xy+y^2)-(x+y)-1/4
=(x+y)^2-(x+y)-1/4
=(x+y-1/2)^2
a^2-10ab+25b^2-5a+25b-6
=(a^2-10ab+25b^2)-(5a-25b)-6
=(a-5b)^2-[(6a-30b)-(a-5b)]-6
=[(a-5b)^2+(a-5b)]-6[(a-5b)+1]
=(a-5b)(a-5b+1)-6(a-5b+1)
=(a-5b+1)(a-5b-6)
3.(C) 4.(D)
参考资料:谢谢楼上的楼上的朋友.
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