若x,y,满足x^2+y^2=5\4,xy=-1\2,求x^3+y^3
3个回答
2018-04-30
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x²+y²=5/4,xy=-1/2,
(x+y)²=(x²+y²)+2xy=5/4-1=1/4,
x+y=1/2,或x+y=-1/2,
x³+y³=(x+y)(x²-xy+y²)=1/2×(5/4+1/2)=7/8,
或,x³+y³=(x+y)(x²-xy+y²)=-1/2×(5/4+1/2)=-7/8,
(x+y)²=(x²+y²)+2xy=5/4-1=1/4,
x+y=1/2,或x+y=-1/2,
x³+y³=(x+y)(x²-xy+y²)=1/2×(5/4+1/2)=7/8,
或,x³+y³=(x+y)(x²-xy+y²)=-1/2×(5/4+1/2)=-7/8,
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