
数学题啊,。!!;;;
2015-12-22 · 知道合伙人教育行家
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2015-12-22 · 知道合伙人金融证券行家
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(x+y)^2-2x-2y+1
=(x+y)^2- 2*(x+y)+1
=(x+y-1)^2
(x^2 + y^2-1)^2-4*x^2*y^2
=(x^2 + y^2-1-2xy)(x^2 + y^2-1+2xy)
=[(x-y)^2-1][(x+y)^2-1]
=(x-y-1)(x-y+1)(x+y-1)(x+y+1)
=(x+y)^2- 2*(x+y)+1
=(x+y-1)^2
(x^2 + y^2-1)^2-4*x^2*y^2
=(x^2 + y^2-1-2xy)(x^2 + y^2-1+2xy)
=[(x-y)^2-1][(x+y)^2-1]
=(x-y-1)(x-y+1)(x+y-1)(x+y+1)
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