Question

火速帮我算一道数学题!!!

a^m=4,a^n=8,则a^4m-2n的值为________

最好有过程!

Answer 1

a^(4m-2n)=a^(4m)/a^(2n)=(a^m)^4/(a^n)^2=4^4/8^2=4

Answer 2

a^4m-2n=a^4m/a^2n=(a^m)^4/(a^n)2^=4^4/8^2=4

Answer 3

a^4m=256
a^2n=64
a^(4m-2n)=256/64=4

Answer 4

a^4m-2n=(a^m)^4/(a^n)^2=64/64=1

Answer 5

a^4m-2n
=(a^m)^4/(a^n)^2
=4^4/8^2
=256/64
=4