Question

求y=ln(x+1)/(x-1)的反函数!

求y=ln(x+1)/(x-1)的反函数!步骤

Answer 1

如图

Answer 2

y=ln[(x+1)/(x-1)],
∴e^y=(x+1)/(x-1),
∴e^y*(x-1)=x+1,
∴(e^y-1)x=e^y+1,
∴x=(e^y+1)/(e^y-1),
x,y互换得y=(e^x+1)/(e^x-1),为所求。