若cos100°=k.则tan(-80°)= 40
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2013-12-02
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tan(-80°)=sin(-80°)/cos(-80°)
=sin(180°-80°)/cos(180°-80°)
=sin(100°)/cos(100°)
sin(100°)=根号(1-cos^2 (100°)) =根号(1-k^2)
tan(-80°)=根号(1-k^2) / k
=sin(180°-80°)/cos(180°-80°)
=sin(100°)/cos(100°)
sin(100°)=根号(1-cos^2 (100°)) =根号(1-k^2)
tan(-80°)=根号(1-k^2) / k
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