Question

log1/2x大于等于1/2. 求x取值范围

底数1/2

Answer 1

x取值范围为：（0，√2/2]
log(1/2)x≥1/log(1/2)√(1/2).
∴x≤√1/2=√2/2
∵x>0
所以：0<x≤√2/2

Answer 2

∵底 =1/2<1 ∴函数递减
∵log1/2(1/2)^(1/2)=1/2
∴0<x<=(1/2)^(1/2)=1/√2=√2/2
x的取值范围：0<x<=√2/2

追问

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