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函数f(x+1)的定义域为[-2,3],
-2<=x<=3
-1<=x+1<=4
即函数f(x)的定义域是[-1,4]
-1<=2x^2-2<=4
1/2<=x^2<=3
x^2>=1/2得:x>=根号2/2或x<=-根号2/2
x^2<=3得-根号3<=X<=根号3
取交集得:根号2/2<=X<=根号3或-根号3<=X<=-根号2/2.
以上即为定义域
-2<=x<=3
-1<=x+1<=4
即函数f(x)的定义域是[-1,4]
-1<=2x^2-2<=4
1/2<=x^2<=3
x^2>=1/2得:x>=根号2/2或x<=-根号2/2
x^2<=3得-根号3<=X<=根号3
取交集得:根号2/2<=X<=根号3或-根号3<=X<=-根号2/2.
以上即为定义域
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