Question

求极限+lim_(x→π/(2))(tanx-6)/(secx+6),用洛必达法则

Answer 1

变形后成为连续的函数。

可直接代入计算：

Answer 2

lim_(x→π/(2))(tanx-6)/(secx+6),
=lim_(x→π/(2))(sec²x)/(secxtanx)
=lim_(x→π/(2))1/sinx
=1