Question

求解下列导数的函数

Answer 1

y = (2+cscx)cotx
y' = -(cscxcotx)cotx - (2+cscx)(cscx)^2
= - cscx(cotx)^2 - (2+cscx)(cscx)^2

Answer 2

u=u(x)，v=v(x)，皆可导
y=uv
y'=u'v＋uv'
此题y=(2＋cscx)cotx
y'=–cscxcot²x–csc²x(2＋cscx)