已知x^2减5x加1=0求x^2 x^2分之一的值
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x²-5x+1=0
x²=5x-1
x²+1/x²
=5x-1+1/(5x-1)
=(25x²-10x+1+1）/(5x-1)
=(125x-25-10x+2)/(5x-1)
=(115x-23)/(5x-1)
=23X(5x-1)/(5x-1)
=23
x²=5x-1
x²+1/x²
=5x-1+1/(5x-1)
=(25x²-10x+1+1）/(5x-1)
=(125x-25-10x+2)/(5x-1)
=(115x-23)/(5x-1)
=23X(5x-1)/(5x-1)
=23
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