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先化简,再求值:1x2?x?x2?2x+1x+1x2,其中x=2
1个回答
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1 |
x2?x |
x2?2x+1 |
x |
1 |
x2 |
=
1 |
x(x?1) |
(x?1)2 |
x |
1 |
x2 |
=
x?1 |
x2 |
1 |
x2 |
=
x |
x2 |
=
1 |
x |
当x=
2 |
1 | ||
|
| ||
2 |
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1 |
x2?x |
x2?2x+1 |
x |
1 |
x2 |
1 |
x(x?1) |
(x?1)2 |
x |
1 |
x2 |
x?1 |
x2 |
1 |
x2 |
x |
x2 |
1 |
x |
2 |
1 | ||
|
| ||
2 |
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