Question

高二 数学 函数问题....... 请详细解答,谢谢! (24 11:13:29)

已知函数f(x)=2cos xsin[x+(π/3)]－(√3)/2
请写出过程，谢谢

Answer 1

已知函数，要干吗？就化简？求最小正周期？？

说清楚嘛~

Answer 2

f(x)=2cosx[sinxcos(π/3)+cosxsin(π/3)]-sin(π/3)
=2cosxsinxcos(π/3)+2cosx*cosxsin(π/3)-sin(π/3)
=sin2xcos(π/3)+(2cosx*cosx-1)sin(π/3)
=sin2xcos(π/3)+cos2xsin(π/3)
=sin(2x+π/3)