X-2的绝对值加x减一的绝对值等于五?
展开全部
答案是 x=4 或 x=-1,这道题要分三段判断和计算。
|x-2| + |x-1| = 5
1) x ≧ 2时,x-2 ≧0 & x-1>0
|x-2| + |x-1| = 5
=> x-2 + x-1 = 5
=> x= 4
2) 1<x<2时,x-2 <0 & x-1>0
|x-2| + |x-1| = 5
=> -(x-2) + (x-1) = 5
方程无解
3)x<≦1时,x-2 <0 & x-1<0
|x-2| + |x-1| = 5
=> -(x-2) - (x-1) = 5
=> -x +2 - x-+1 = 5
=> x=-1
|x-2| + |x-1| = 5
1) x ≧ 2时,x-2 ≧0 & x-1>0
|x-2| + |x-1| = 5
=> x-2 + x-1 = 5
=> x= 4
2) 1<x<2时,x-2 <0 & x-1>0
|x-2| + |x-1| = 5
=> -(x-2) + (x-1) = 5
方程无解
3)x<≦1时,x-2 <0 & x-1<0
|x-2| + |x-1| = 5
=> -(x-2) - (x-1) = 5
=> -x +2 - x-+1 = 5
=> x=-1
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询