Question

高一函数表达法，急急急

已知函数f（x）满足f（a×b)=f(a)+f(b)且f(2)=p,f(3)=q,则f(36)=

Answer 1

f(6)=f(2×3)=f(2)+f(3)=p+q
f(36)=f(6×6)=f(6)+f(6)=2p+2q

Answer 2

f(6)=f(2*3）=f（2）+f（3）=p+q
f(36)=f(6*6)=f(6)+f(6)=2(p+q)