Question

用因式分解法解下列方程3(x-5)²=2(5-x)

麻烦些下详细步骤 谢谢了 O(∩_∩)O哈！

Answer 1

3(x-5)²=2(5-x)
3(x-5)²-2(5-x)=0
3(x-5)²+2(x-5)=0
(x-5)[3(x-5)+2]=0
(x-5)[3x-15+2]=0
(x-5)[3x-13]=0
x=5或x=13/3

Answer 2

3(x-5)²-2(5-x)=0
3(x-5)²+2(x-5)=0
(x-5)(3x-15+2)=0
(x-5)(3x-13)=0

所以 x=5 或者13/3

Answer 3

3(x-5)²-2(5-x)=3(x-5)²+2(x-5)=(x-5)((3x-5)+2)=(x-5)(3x-3)
=3(x-5)(x-1)

Answer 4

3(x-5)²=2(5-x）
3(x-5)²-2(5-x）=0
3(x-5)²+2(x-5）=(x-5)(3x-13)=0
x1=5,x2=13/3.