数学的通项公式
1个回答
展开全部
a(n+1)= an +3n +2
a(n+1)- an = 3n+2
an- a(n-1) = 3n-2
an - a1 = 1+ 4+....+(3n-2)
= (3n-1)(n-1)/2
an = (3n-1)(n-1)/2 + 2
= (3n^2-4n+5)/2
a(n+1)- an = 3n+2
an- a(n-1) = 3n-2
an - a1 = 1+ 4+....+(3n-2)
= (3n-1)(n-1)/2
an = (3n-1)(n-1)/2 + 2
= (3n^2-4n+5)/2
本回答被网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询