Question

解不等式 (x-1)(x-2)+(x-2)(x-3)-2(x-3)(x-4)＜—4

急~~~~~~~急~~~~~~~~~~~急~~~~~~~~~急 也要过程

Answer 1

(x-1)(x-2)+(x-2)(x-3)-2(x-3)(x-4)＜—4
x²-3x+2+x²-5x+6-2x²+14x-24＜—4
6x-16＜—4
6x＜12
x＜2

Answer 2

(x-1)(x-2)+(x-2)(x-3)-2(x-3)(x-4)＜-4
x^2-3x+2+x^2-5x+6-2(x^2-7x+12)+4<0
6x-12<0
x<2