Question

求∫2xcosx∧2的不定积分 请把解题步骤写下来

Answer 1

∫2xcosx∧2dx
=∫x(cos2x+1)dx
=x^2/2+(1/2)∫xdsin2x
=x^2/2+(1/2)xdsin2x-(1/2)∫sin2xdx
=x^2/2+(1/2)xdsin2x+(1/4)∫dcos2x
=x^2/2+(1/2)xdsin2x+(1/4)dcos2x+c