Question

数学代数式

数学代数、先化简在求值、怎么算吖？帮帮我吧、
1： 2(2^2b+ab^2)-2(a^2b-1)-2ab^2-2其中a=-2 b=2 （还有格式、代如上式、得XXXXX
2：5X^4+3x^2y-10-3x^2y+x4-1
3：P^2+3pq+6-8p^2+pq

Answer 1

1:2(a^2b+ab^2)-2(a^2b-1)-2ab^2-2
=2a^2b+2ab^2-2a^2b+2-2ab^2-2
=0
当a=-2,b=2时，原式＝0
2：5X^4+3x^2y-10-3x^2y+x4-1
＝6x^4-11
3:P^2+3pq+6-8p^2+pq
=-7p^2+4pq-6

Answer 2

1.2(2^2b+ab^2)-2(a^2b-1)-2ab^2-2=8b+2ab^2-2a^2b+2-2ab^2-2=8b-2a^2
a=-2,b=2代入上式
8b-2a^2b=8*2-2*4*2=0
2.5x^4+3x^2y-10-3x^2y+x^4-1=6x^4-11
3.p^2+3pq+6-8p^2+pq=-7p^2+4pq+6